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120131031041 = 749134952293
BaseRepresentation
bin110111111100001011…
…1100001000000000001
3102111002010201200021222
41233320113201000001
53432012020443131
6131104252524425
711451646626050
oct1577027410001
9374063650258
10120131031041
1146a4692073a
121b347780715
13b4363a4228
145b588d4397
1531d173987b
hex1bf85e1001

120131031041 has 8 divisors (see below), whose sum is σ = 137572229184. Its totient is φ = 102759738480.

The previous prime is 120131030993. The next prime is 120131031047. The reversal of 120131031041 is 140130131021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 120131031041 - 214 = 120131014657 is a prime.

It is a super-4 number, since 4×1201310310414 (a number of 45 digits) contains 4444 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (120131031047) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17472710 + ... + 17479583.

It is an arithmetic number, because the mean of its divisors is an integer number (17196528648).

Almost surely, 2120131031041 is an apocalyptic number.

It is an amenable number.

120131031041 is a deficient number, since it is larger than the sum of its proper divisors (17441198143).

120131031041 is an equidigital number, since it uses as much as digits as its factorization.

120131031041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34952791.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 120131031041 its reverse (140130131021), we get a palindrome (260261162062).

The spelling of 120131031041 in words is "one hundred twenty billion, one hundred thirty-one million, thirty-one thousand, forty-one".

Divisors: 1 7 491 3437 34952293 244666051 17161575863 120131031041