12013103221331 has 4 divisors (see below), whose sum is σ = 12123315177600. Its totient is φ = 11902891265064.

The previous prime is 12013103221297. The next prime is 12013103221387. The reversal of 12013103221331 is 13312230131021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12013103221331 is a prime.

It is a super-2 number, since 2×12013103221331² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12013103221297 and 12013103221306.

It is not an unprimeable number, because it can be changed into a prime (12013103220331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55105977971 + ... + 55105978188.

It is an arithmetic number, because the mean of its divisors is an integer number (3030828794400).

Almost surely, 2^{12013103221331} is an apocalyptic number.

12013103221331 is a deficient number, since it is larger than the sum of its proper divisors (110211956269).

12013103221331 is a wasteful number, since it uses less digits than its factorization.

12013103221331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110211956268.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 12013103221331 its reverse (13312230131021), we get a palindrome (25325333352352).

The spelling of 12013103221331 in words is "twelve trillion, thirteen billion, one hundred three million, two hundred twenty-one thousand, three hundred thirty-one".