Base | Representation |
---|---|
bin | 10110011000000100… |
… | …10110100011011011 |
3 | 1011000012202212201201 |
4 | 23030002112203123 |
5 | 144100323301243 |
6 | 5304014255031 |
7 | 603460456564 |
oct | 131402264333 |
9 | 34005685651 |
10 | 12013103323 |
11 | 51050a1371 |
12 | 23b31b7477 |
13 | 1195aa1a80 |
14 | 81d66d16b |
15 | 4a49ad04d |
hex | 2cc0968db |
12013103323 has 8 divisors (see below), whose sum is σ = 12939702048. Its totient is φ = 11086863744.
The previous prime is 12013103303. The next prime is 12013103327. The reversal of 12013103323 is 32330131021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12013103323 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12013103323.
It is not an unprimeable number, because it can be changed into a prime (12013103327) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18190 + ... + 156067.
It is an arithmetic number, because the mean of its divisors is an integer number (1617462756).
Almost surely, 212013103323 is an apocalyptic number.
12013103323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12013103323 is a deficient number, since it is larger than the sum of its proper divisors (926598725).
12013103323 is a wasteful number, since it uses less digits than its factorization.
12013103323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 179573.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 12013103323 its reverse (32330131021), we get a palindrome (44343234344).
The spelling of 12013103323 in words is "twelve billion, thirteen million, one hundred three thousand, three hundred twenty-three".
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