Base | Representation |
---|---|
bin | 10110011000000100… |
… | …10111100101010000 |
3 | 1011000012210002111202 |
4 | 23030002113211100 |
5 | 144100323420121 |
6 | 5304014330332 |
7 | 603460505063 |
oct | 131402274520 |
9 | 34005702452 |
10 | 12013107536 |
11 | 51050a4551 |
12 | 23b31b99a8 |
13 | 1195aa3971 |
14 | 81d6708da |
15 | 4a49ae40b |
hex | 2cc097950 |
12013107536 has 20 divisors (see below), whose sum is σ = 23501373792. Its totient is φ = 5948236896.
The previous prime is 12013107527. The next prime is 12013107539. The reversal of 12013107536 is 63570131021.
It is a junction number, because it is equal to n+sod(n) for n = 12013107499 and 12013107508.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12013107539) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3643106 + ... + 3646401.
Almost surely, 212013107536 is an apocalyptic number.
12013107536 is a gapful number since it is divisible by the number (16) formed by its first and last digit.
It is an amenable number.
12013107536 is a deficient number, since it is larger than the sum of its proper divisors (11488266256).
12013107536 is a wasteful number, since it uses less digits than its factorization.
12013107536 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7289618 (or 7289612 counting only the distinct ones).
The product of its (nonzero) digits is 3780, while the sum is 29.
Adding to 12013107536 its reverse (63570131021), we get a palindrome (75583238557).
The spelling of 12013107536 in words is "twelve billion, thirteen million, one hundred seven thousand, five hundred thirty-six".
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