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1201311002011 = 1893116345701
BaseRepresentation
bin10001011110110011101…
…101110010110110011011
311020211210102120220122111
4101132303231302312123
5124140241104031021
62315512531533151
7152535415015231
oct21366355626633
94224712526574
101201311002011
1142352281932a
121749a475a1b7
138938b0a5643
14422026b0951
15213aed508e1
hex117b3b72d9b

1201311002011 has 4 divisors (see below), whose sum is σ = 1201317537024. Its totient is φ = 1201304467000.

The previous prime is 1201311001999. The next prime is 1201311002039. The reversal of 1201311002011 is 1102001131021.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1201311002011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1201311001982 and 1201311002000.

It is not an unprimeable number, because it can be changed into a prime (1201311002711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2983540 + ... + 3362161.

It is an arithmetic number, because the mean of its divisors is an integer number (300329384256).

Almost surely, 21201311002011 is an apocalyptic number.

1201311002011 is a deficient number, since it is larger than the sum of its proper divisors (6535013).

1201311002011 is an equidigital number, since it uses as much as digits as its factorization.

1201311002011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6535012.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1201311002011 its reverse (1102001131021), we get a palindrome (2303312133032).

The spelling of 1201311002011 in words is "one trillion, two hundred one billion, three hundred eleven million, two thousand, eleven".

Divisors: 1 189311 6345701 1201311002011