12013114140312 has 32 divisors (see below), whose sum is σ = 30118839198000. Its totient is φ = 3992897533824.

The previous prime is 12013114140253. The next prime is 12013114140343. The reversal of 12013114140312 is 21304141131021.

It is a super-2 number, since 2×12013114140312² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 717106843 + ... + 717123594.

Almost surely, 2^{12013114140312} is an apocalyptic number.

12013114140312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

12013114140312 is an abundant number, since it is smaller than the sum of its proper divisors (18105725057688).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12013114140312 is a wasteful number, since it uses less digits than its factorization.

12013114140312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1434230795 (or 1434230791 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 12013114140312 its reverse (21304141131021), we get a palindrome (33317255271333).

The spelling of 12013114140312 in words is "twelve trillion, thirteen billion, one hundred fourteen million, one hundred forty thousand, three hundred twelve".