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120131233323132 = 22341695935086819
BaseRepresentation
bin11011010100001000111011…
…011111010001100001111100
3120202100102201012102120211210
4123110020323133101201330
5111221212231212320012
61103255305434244420
734206123644055603
oct3324107337214174
9522312635376753
10120131233323132
113530640843a259
12115822a2b86710
1352054329923b5
142194550260a3a
15dd4d508d823c
hex6d423b7d187c

120131233323132 has 48 divisors (see below), whose sum is σ = 287184218227200. Its totient is φ = 39061452743040.

The previous prime is 120131233323131. The next prime is 120131233323133. The reversal of 120131233323132 is 231323332131021.

120131233323132 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (120131233323131) and next prime (120131233323133).

It is a self number, because there is not a number n which added to its sum of digits gives 120131233323132.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120131233323131) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14119582 + ... + 20967237.

It is an arithmetic number, because the mean of its divisors is an integer number (5983004546400).

Almost surely, 2120131233323132 is an apocalyptic number.

120131233323132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

120131233323132 is an abundant number, since it is smaller than the sum of its proper divisors (167052984904068).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120131233323132 is a wasteful number, since it uses less digits than its factorization.

120131233323132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35093826 (or 35093824 counting only the distinct ones).

The product of its (nonzero) digits is 11664, while the sum is 30.

Adding to 120131233323132 its reverse (231323332131021), we get a palindrome (351454565454153).

The spelling of 120131233323132 in words is "one hundred twenty trillion, one hundred thirty-one billion, two hundred thirty-three million, three hundred twenty-three thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 12 41 82 123 164 246 492 6959 13918 20877 27836 41754 83508 285319 570638 855957 1141276 1711914 3423828 35086819 70173638 105260457 140347276 210520914 421041828 1438559579 2877119158 4315678737 5754238316 8631357474 17262714948 244169173421 488338346842 732507520263 976676693684 1465015040526 2930030081052 10010936110261 20021872220522 30032808330783 40043744441044 60065616661566 120131233323132