Base | Representation |
---|---|
bin | 10110011000000100… |
… | …11011011100010111 |
3 | 1011000012210220012111 |
4 | 23030002123130113 |
5 | 144100324421401 |
6 | 5304014531451 |
7 | 603460602145 |
oct | 131402333427 |
9 | 34005726174 |
10 | 12013123351 |
11 | 5105105419 |
12 | 23b3206b87 |
13 | 1195aaac18 |
14 | 81d676595 |
15 | 4a49b3e51 |
hex | 2cc09b717 |
12013123351 has 2 divisors, whose sum is σ = 12013123352. Its totient is φ = 12013123350.
The previous prime is 12013123211. The next prime is 12013123403. The reversal of 12013123351 is 15332131021.
12013123351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (15332131021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12013123351 - 29 = 12013122839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12013120351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006561675 + 6006561676.
It is an arithmetic number, because the mean of its divisors is an integer number (6006561676).
Almost surely, 212013123351 is an apocalyptic number.
12013123351 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013123351 is an equidigital number, since it uses as much as digits as its factorization.
12013123351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 12013123351 its reverse (15332131021), we get a palindrome (27345254372).
The spelling of 12013123351 in words is "twelve billion, thirteen million, one hundred twenty-three thousand, three hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.031 sec. • engine limits •