Base | Representation |
---|---|
bin | 10110011000000100… |
… | …11011011101110010 |
3 | 1011000012210220022212 |
4 | 23030002123131302 |
5 | 144100324422232 |
6 | 5304014532122 |
7 | 603460602335 |
oct | 131402333562 |
9 | 34005726285 |
10 | 12013123442 |
11 | 51051054a1 |
12 | 23b3207042 |
13 | 1195aaac88 |
14 | 81d67661c |
15 | 4a49b3eb2 |
hex | 2cc09b772 |
12013123442 has 4 divisors (see below), whose sum is σ = 18019685166. Its totient is φ = 6006561720.
The previous prime is 12013123439. The next prime is 12013123453. The reversal of 12013123442 is 24432131021.
12013123442 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24432131021 = 96661 ⋅252761.
It can be written as a sum of positive squares in only one way, i.e., 11848540201 + 164583241 = 108851^2 + 12829^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3003280859 + ... + 3003280862.
Almost surely, 212013123442 is an apocalyptic number.
12013123442 is a deficient number, since it is larger than the sum of its proper divisors (6006561724).
12013123442 is an equidigital number, since it uses as much as digits as its factorization.
12013123442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6006561723.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 12013123442 its reverse (24432131021), we get a palindrome (36445254463).
The spelling of 12013123442 in words is "twelve billion, thirteen million, one hundred twenty-three thousand, four hundred forty-two".
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