120131314004011 has 4 divisors (see below), whose sum is σ = 120139652417392. Its totient is φ = 120122975590632.

The previous prime is 120131314003999. The next prime is 120131314004087. The reversal of 120131314004011 is 110400413131021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120131314004011 - 2²³ = 120131305615403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120131314004111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4169185080 + ... + 4169213893.

It is an arithmetic number, because the mean of its divisors is an integer number (30034913104348).

Almost surely, 2^{120131314004011} is an apocalyptic number.

120131314004011 is a deficient number, since it is larger than the sum of its proper divisors (8338413381).

120131314004011 is an equidigital number, since it uses as much as digits as its factorization.

120131314004011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8338413380.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 120131314004011 its reverse (110400413131021), we get a palindrome (230531727135032).

The spelling of 120131314004011 in words is "one hundred twenty trillion, one hundred thirty-one billion, three hundred fourteen million, four thousand, eleven".