1201314044203 has 24 divisors (see below), whose sum is σ = 1505328846000. Its totient is φ = 950246458560.

The previous prime is 1201314044159. The next prime is 1201314044219. The reversal of 1201314044203 is 3024404131021.

It is not a de Polignac number, because 1201314044203 - 2²¹ = 1201311947051 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1201314044243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2264173 + ... + 2743921.

It is an arithmetic number, because the mean of its divisors is an integer number (62722035250).

Almost surely, 2^{1201314044203} is an apocalyptic number.

1201314044203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1201314044203 is a deficient number, since it is larger than the sum of its proper divisors (304014801797).

1201314044203 is a wasteful number, since it uses less digits than its factorization.

1201314044203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 483707 (or 483700 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1201314044203 its reverse (3024404131021), we get a palindrome (4225718175224).

The spelling of 1201314044203 in words is "one trillion, two hundred one billion, three hundred fourteen million, forty-four thousand, two hundred three".