120131421132 has 12 divisors (see below), whose sum is σ = 280306649336. Its totient is φ = 40043807040.

The previous prime is 120131421083. The next prime is 120131421133. The reversal of 120131421132 is 231124131021.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×120131421132² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 120131421099 and 120131421108.

It is not an unprimeable number, because it can be changed into a prime (120131421133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5005475869 + ... + 5005475892.

Almost surely, 2^120131421132 is an apocalyptic number.

120131421132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

120131421132 is an abundant number, since it is smaller than the sum of its proper divisors (160175228204).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120131421132 is a wasteful number, since it uses less digits than its factorization.

120131421132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10010951768 (or 10010951766 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 120131421132 its reverse (231124131021), we get a palindrome (351255552153).

The spelling of 120131421132 in words is "one hundred twenty billion, one hundred thirty-one million, four hundred twenty-one thousand, one hundred thirty-two".