Base | Representation |
---|---|
bin | 1010111011010000011110… |
… | …1010100110100101001100 |
3 | 1120112110001020010210221002 |
4 | 2232310013222212211030 |
5 | 3033310413421314000 |
6 | 41314433233555432 |
7 | 2346631052222615 |
oct | 256640752464514 |
9 | 46473036123832 |
10 | 12013152135500 |
11 | 391182721a97a |
12 | 1420290415b78 |
13 | 691ab245a499 |
14 | 2d762262ac0c |
15 | 15c7528c48d5 |
hex | aed07aa694c |
12013152135500 has 48 divisors (see below), whose sum is σ = 26240197043424. Its totient is φ = 4804624814400.
The previous prime is 12013152135493. The next prime is 12013152135553. The reversal of 12013152135500 is 553125131021.
12013152135500 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2200187 + ... + 5372813.
It is an arithmetic number, because the mean of its divisors is an integer number (546670771738).
Almost surely, 212013152135500 is an apocalyptic number.
12013152135500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12013152135500 is an abundant number, since it is smaller than the sum of its proper divisors (14227044907924).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12013152135500 is a wasteful number, since it uses less digits than its factorization.
12013152135500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3180219 (or 3180207 counting only the distinct ones).
The product of its (nonzero) digits is 4500, while the sum is 29.
Adding to 12013152135500 its reverse (553125131021), we get a palindrome (12566277266521).
The spelling of 12013152135500 in words is "twelve trillion, thirteen billion, one hundred fifty-two million, one hundred thirty-five thousand, five hundred".
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