12013199983 has 2 divisors, whose sum is σ = 12013199984. Its totient is φ = 12013199982.

The previous prime is 12013199969. The next prime is 12013199987. The reversal of 12013199983 is 38999131021.

12013199983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (38999131021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12013199983 - 2²⁹ = 11476329071 is a prime.

It is a super-3 number, since 3×12013199983³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12013199987) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006599991 + 6006599992.

It is an arithmetic number, because the mean of its divisors is an integer number (6006599992).

Almost surely, 2^12013199983 is an apocalyptic number.

12013199983 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013199983 is an equidigital number, since it uses as much as digits as its factorization.

12013199983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 104976, while the sum is 46.

The spelling of 12013199983 in words is "twelve billion, thirteen million, one hundred ninety-nine thousand, nine hundred eighty-three".