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120132010011002 = 2115460545909591
BaseRepresentation
bin11011010100001001101001…
…110010000110100101111010
3120202100111201022220102022012
4123110021221302012211322
5111221220324030323002
61103255514501325522
734206152124566663
oct3324115162064572
9522314638812265
10120132010011002
11353067768a8360
121158247b1068a2
135205527872412
1421945c547c36a
15dd4d98ba7d52
hex6d4269c8697a

120132010011002 has 8 divisors (see below), whose sum is σ = 196579652745312. Its totient is φ = 54605459095900.

The previous prime is 120132010010959. The next prime is 120132010011037. The reversal of 120132010011002 is 200110010231021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1201320100110022 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2730272954774 + ... + 2730272954817.

It is an arithmetic number, because the mean of its divisors is an integer number (24572456593164).

Almost surely, 2120132010011002 is an apocalyptic number.

120132010011002 is a deficient number, since it is larger than the sum of its proper divisors (76447642734310).

120132010011002 is a wasteful number, since it uses less digits than its factorization.

120132010011002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5460545909604.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 120132010011002 its reverse (200110010231021), we get a palindrome (320242020242023).

The spelling of 120132010011002 in words is "one hundred twenty trillion, one hundred thirty-two billion, ten million, eleven thousand, two".

Divisors: 1 2 11 22 5460545909591 10921091819182 60066005005501 120132010011002