Base | Representation |
---|---|
bin | 100011110011010… |
… | …1011000010111011 |
3 | 10002201111101101220 |
4 | 1013212223002323 |
5 | 4430014220443 |
6 | 315112243123 |
7 | 41525024013 |
oct | 10746530273 |
9 | 3081441356 |
10 | 1201320123 |
11 | 567128653 |
12 | 2963a04a3 |
13 | 161b67313 |
14 | b5794c43 |
15 | 706eba83 |
hex | 479ab0bb |
1201320123 has 4 divisors (see below), whose sum is σ = 1601760168. Its totient is φ = 800880080.
The previous prime is 1201320121. The next prime is 1201320143. The reversal of 1201320123 is 3210231021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1201320123 - 21 = 1201320121 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1201320121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200220018 + ... + 200220023.
It is an arithmetic number, because the mean of its divisors is an integer number (400440042).
Almost surely, 21201320123 is an apocalyptic number.
1201320123 is a deficient number, since it is larger than the sum of its proper divisors (400440045).
1201320123 is an equidigital number, since it uses as much as digits as its factorization.
1201320123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 400440044.
The product of its (nonzero) digits is 72, while the sum is 15.
The square root of 1201320123 is about 34660.0652480632. The cubic root of 1201320123 is about 1063.0481041576.
Adding to 1201320123 its reverse (3210231021), we get a palindrome (4411551144).
The spelling of 1201320123 in words is "one billion, two hundred one million, three hundred twenty thousand, one hundred twenty-three".
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