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120132021223 is a prime number
BaseRepresentation
bin110111111100001101…
…1010010101111100111
3102111002012120222120101
41233320123102233213
53432012244134343
6131104330044531
711451661221634
oct1577033225747
9374065528511
10120132021223
1146a47437675
121b347b79747
13b43665cb36
145b58ab118b
1531d1882e4d
hex1bf86d2be7

120132021223 has 2 divisors, whose sum is σ = 120132021224. Its totient is φ = 120132021222.

The previous prime is 120132021157. The next prime is 120132021323. The reversal of 120132021223 is 322120231021.

It is a weak prime.

It is an emirp because it is prime and its reverse (322120231021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120132021223 - 29 = 120132020711 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 120132021223.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120132021323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066010611 + 60066010612.

It is an arithmetic number, because the mean of its divisors is an integer number (60066010612).

Almost surely, 2120132021223 is an apocalyptic number.

120132021223 is a deficient number, since it is larger than the sum of its proper divisors (1).

120132021223 is an equidigital number, since it uses as much as digits as its factorization.

120132021223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 120132021223 its reverse (322120231021), we get a palindrome (442252252244).

The spelling of 120132021223 in words is "one hundred twenty billion, one hundred thirty-two million, twenty-one thousand, two hundred twenty-three".