Base | Representation |
---|---|
bin | 1010111011010000101100… |
… | …1111000001000111001001 |
3 | 1120112110012101210220102022 |
4 | 2232310023033001013021 |
5 | 3033311024233404001 |
6 | 41314443213214225 |
7 | 2346632410166603 |
oct | 256641317010711 |
9 | 46473171726368 |
10 | 12013212013001 |
11 | 3911857aa7811 |
12 | 14202a8491375 |
13 | 691ac1993764 |
14 | 2d762a576173 |
15 | 15c757ca111b |
hex | aed0b3c11c9 |
12013212013001 has 4 divisors (see below), whose sum is σ = 12013352052612. Its totient is φ = 12013071973392.
The previous prime is 12013212012961. The next prime is 12013212013013. The reversal of 12013212013001 is 10031021231021.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 11467942009225 + 545270003776 = 3386435^2 + 738424^2 .
It is a cyclic number.
It is not a de Polignac number, because 12013212013001 - 222 = 12013207818697 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12013212013801) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69891050 + ... + 70062723.
It is an arithmetic number, because the mean of its divisors is an integer number (3003338013153).
Almost surely, 212013212013001 is an apocalyptic number.
It is an amenable number.
12013212013001 is a deficient number, since it is larger than the sum of its proper divisors (140039611).
12013212013001 is an equidigital number, since it uses as much as digits as its factorization.
12013212013001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 140039610.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 12013212013001 its reverse (10031021231021), we get a palindrome (22044233244022).
The spelling of 12013212013001 in words is "twelve trillion, thirteen billion, two hundred twelve million, thirteen thousand, one".
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