Base | Representation |
---|---|
bin | 10110011000000101… |
… | …10011100011110011 |
3 | 1011000012222220201000 |
4 | 23030002303203303 |
5 | 144100341102011 |
6 | 5304021013043 |
7 | 603461463141 |
oct | 131402634363 |
9 | 34005886630 |
10 | 12013222131 |
11 | 5105172659 |
12 | 23b3254183 |
13 | 1195b13b81 |
14 | 81d6a0591 |
15 | 4a49d3356 |
hex | 2cc0b38f3 |
12013222131 has 64 divisors (see below), whose sum is σ = 19483200000. Its totient is φ = 7286702976.
The previous prime is 12013222037. The next prime is 12013222163. The reversal of 12013222131 is 13122231021.
12013222131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12013222131 - 27 = 12013222003 is a prime.
It is a super-2 number, since 2×120132221312 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12013222181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2928720 + ... + 2932818.
It is an arithmetic number, because the mean of its divisors is an integer number (304425000).
Almost surely, 212013222131 is an apocalyptic number.
12013222131 is a deficient number, since it is larger than the sum of its proper divisors (7469977869).
12013222131 is a wasteful number, since it uses less digits than its factorization.
12013222131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4353 (or 4347 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 12013222131 its reverse (13122231021), we get a palindrome (25135453152).
The spelling of 12013222131 in words is "twelve billion, thirteen million, two hundred twenty-two thousand, one hundred thirty-one".
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