1201323321133 has 4 divisors (see below), whose sum is σ = 1293732807388. Its totient is φ = 1108913834880.

The previous prime is 1201323321131. The next prime is 1201323321139. The reversal of 1201323321133 is 3311233231021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 298637111529 + 902686209604 = 546477^2 + 950098^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201323321133 - 2¹ = 1201323321131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1201323321098 and 1201323321107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201323321131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46204743108 + ... + 46204743133.

It is an arithmetic number, because the mean of its divisors is an integer number (323433201847).

Almost surely, 2^{1201323321133} is an apocalyptic number.

1201323321133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1201323321133 is a deficient number, since it is larger than the sum of its proper divisors (92409486255).

1201323321133 is an equidigital number, since it uses as much as digits as its factorization.

1201323321133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 92409486254.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1201323321133 its reverse (3311233231021), we get a palindrome (4512556552154).

The spelling of 1201323321133 in words is "one trillion, two hundred one billion, three hundred twenty-three million, three hundred twenty-one thousand, one hundred thirty-three".