Base | Representation |
---|---|
bin | 11011010100001010000001… |
… | …010110011011101000011100 |
3 | 120202100112201212220210012211 |
4 | 123110022001112123220130 |
5 | 111221222131241112312 |
6 | 1103300022024210204 |
7 | 34206164665460500 |
oct | 3324120126335034 |
9 | 522315655823184 |
10 | 120132405410332 |
11 | 3530695a010767 |
12 | 1158256b609964 |
13 | 520558b762913 |
14 | 2194621ba6300 |
15 | dd4dbd75d3a7 |
hex | 6d428159ba1c |
120132405410332 has 18 divisors (see below), whose sum is σ = 244555253871432. Its totient is φ = 51485316604344.
The previous prime is 120132405410179. The next prime is 120132405410333. The reversal of 120132405410332 is 233014504231021.
It is a junction number, because it is equal to n+sod(n) for n = 120132405410294 and 120132405410303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120132405410333) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 306460217688 + ... + 306460218079.
Almost surely, 2120132405410332 is an apocalyptic number.
It is an amenable number.
120132405410332 is an abundant number, since it is smaller than the sum of its proper divisors (124422848461100).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120132405410332 is a wasteful number, since it uses less digits than its factorization.
120132405410332 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 612920435785 (or 612920435776 counting only the distinct ones).
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 120132405410332 its reverse (233014504231021), we get a palindrome (353146909641353).
The spelling of 120132405410332 in words is "one hundred twenty trillion, one hundred thirty-two billion, four hundred five million, four hundred ten thousand, three hundred thirty-two".
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