Base | Representation |
---|---|
bin | 11011010100001010100111… |
… | …100011010001100111110010 |
3 | 120202100121101112212221012210 |
4 | 123110022213203101213302 |
5 | 111221224434323431120 |
6 | 1103300205401032550 |
7 | 34206216610156656 |
oct | 3324124743214762 |
9 | 522317345787183 |
10 | 120133046311410 |
11 | 35307158865180 |
12 | 1158270a185756 |
13 | 520566147c222 |
14 | 2194682d58a66 |
15 | dd4e09b59ce0 |
hex | 6d42a78d19f2 |
120133046311410 has 32 divisors (see below), whose sum is σ = 314530157616192. Its totient is φ = 29123162742080.
The previous prime is 120133046311373. The next prime is 120133046311429. The reversal of 120133046311410 is 14113640331021.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 182019766809 + ... + 182019767468.
It is an arithmetic number, because the mean of its divisors is an integer number (9829067425506).
Almost surely, 2120133046311410 is an apocalyptic number.
120133046311410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
120133046311410 is an abundant number, since it is smaller than the sum of its proper divisors (194397111304782).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120133046311410 is a wasteful number, since it uses less digits than its factorization.
120133046311410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 364039534298.
The product of its (nonzero) digits is 5184, while the sum is 30.
Adding to 120133046311410 its reverse (14113640331021), we get a palindrome (134246686642431).
The spelling of 120133046311410 in words is "one hundred twenty trillion, one hundred thirty-three billion, forty-six million, three hundred eleven thousand, four hundred ten".
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