Base | Representation |
---|---|
bin | 10001011110110100111… |
… | …010011110000110110010 |
3 | 11020211211211102002211100 |
4 | 101132310322132012302 |
5 | 124140311230232010 |
6 | 2315514530425230 |
7 | 152536050612165 |
oct | 21366472360662 |
9 | 4224754362740 |
10 | 1201331102130 |
11 | 4235330a78a5 |
12 | 1749ab432216 |
13 | 893922c24c3 |
14 | 42205223adc |
15 | 213b19c12c0 |
hex | 117b4e9e1b2 |
1201331102130 has 48 divisors (see below), whose sum is σ = 3127183899840. Its totient is φ = 319973110944.
The previous prime is 1201331102129. The next prime is 1201331102161. The reversal of 1201331102130 is 312011331021.
1201331102130 is a `hidden beast` number, since 1 + 201 + 331 + 1 + 0 + 2 + 130 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7879272 + ... + 8030291.
It is an arithmetic number, because the mean of its divisors is an integer number (65149664580).
Almost surely, 21201331102130 is an apocalyptic number.
1201331102130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1201331102130 is an abundant number, since it is smaller than the sum of its proper divisors (1925852797710).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1201331102130 is a wasteful number, since it uses less digits than its factorization.
1201331102130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15910415 (or 15910412 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 1201331102130 its reverse (312011331021), we get a palindrome (1513342433151).
The spelling of 1201331102130 in words is "one trillion, two hundred one billion, three hundred thirty-one million, one hundred two thousand, one hundred thirty".
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