Base | Representation |
---|---|
bin | 1010111011010001000110… |
… | …1111100010000110001011 |
3 | 1120112110111000021011211122 |
4 | 2232310101233202012023 |
5 | 3033311240211400021 |
6 | 41314502113345455 |
7 | 2346635204234225 |
oct | 256642157420613 |
9 | 46473430234748 |
10 | 12013321200011 |
11 | 39119036a360a |
12 | 1420318b6828b |
13 | 691b0b4a2a61 |
14 | 2d763ac79415 |
15 | 15c76266cbab |
hex | aed11be218b |
12013321200011 has 4 divisors (see below), whose sum is σ = 12014114226000. Its totient is φ = 12012528174024.
The previous prime is 12013321199909. The next prime is 12013321200043. The reversal of 12013321200011 is 11000212331021.
12013321200011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12013321200011 - 242 = 7615274688907 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12013321200091) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 396490271 + ... + 396520568.
It is an arithmetic number, because the mean of its divisors is an integer number (3003528556500).
Almost surely, 212013321200011 is an apocalyptic number.
12013321200011 is a deficient number, since it is larger than the sum of its proper divisors (793025989).
12013321200011 is an equidigital number, since it uses as much as digits as its factorization.
12013321200011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 793025988.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 12013321200011 its reverse (11000212331021), we get a palindrome (23013533531032).
The spelling of 12013321200011 in words is "twelve trillion, thirteen billion, three hundred twenty-one million, two hundred thousand, eleven".
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