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120133302013111 is a prime number
BaseRepresentation
bin11011010100001010110110…
…110010101100110010110111
3120202100122001101000221000011
4123110022312302230302313
5111221231000303404421
61103300251013401051
734206226133456662
oct3324126662546267
9522318041027004
10120133302013111
113530727a1326a2
121158277b939187
1352056a2439bca
1421946a8cba6d9
15dd4e223184e1
hex6d42b6caccb7

120133302013111 has 2 divisors, whose sum is σ = 120133302013112. Its totient is φ = 120133302013110.

The previous prime is 120133302013103. The next prime is 120133302013121. The reversal of 120133302013111 is 111310203331021.

It is a weak prime.

It is an emirp because it is prime and its reverse (111310203331021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120133302013111 - 23 = 120133302013103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120133302013121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066651006555 + 60066651006556.

It is an arithmetic number, because the mean of its divisors is an integer number (60066651006556).

Almost surely, 2120133302013111 is an apocalyptic number.

120133302013111 is a deficient number, since it is larger than the sum of its proper divisors (1).

120133302013111 is an equidigital number, since it uses as much as digits as its factorization.

120133302013111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 120133302013111 its reverse (111310203331021), we get a palindrome (231443505344132).

The spelling of 120133302013111 in words is "one hundred twenty trillion, one hundred thirty-three billion, three hundred two million, thirteen thousand, one hundred eleven".