12013344535 has 4 divisors (see below), whose sum is σ = 14416013448. Its totient is φ = 9610675624.

The previous prime is 12013344527. The next prime is 12013344547. The reversal of 12013344535 is 53544331021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53544331021 = 137 ⋅390834533.

It is a cyclic number.

It is not a de Polignac number, because 12013344535 - 2³ = 12013344527 is a prime.

It is a super-2 number, since 2×12013344535² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12013344497 and 12013344506.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1201334449 + ... + 1201334458.

It is an arithmetic number, because the mean of its divisors is an integer number (3604003362).

Almost surely, 2^12013344535 is an apocalyptic number.

12013344535 is a deficient number, since it is larger than the sum of its proper divisors (2402668913).

12013344535 is an equidigital number, since it uses as much as digits as its factorization.

12013344535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2402668912.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 12013344535 its reverse (53544331021), we get a palindrome (65557675556).

The spelling of 12013344535 in words is "twelve billion, thirteen million, three hundred forty-four thousand, five hundred thirty-five".