1201340001031 has 4 divisors (see below), whose sum is σ = 1201343155200. Its totient is φ = 1201336846864.

The previous prime is 1201340000981. The next prime is 1201340001053. The reversal of 1201340001031 is 1301000431021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1201340001031 - 2²³ = 1201331612423 is a prime.

It is a super-2 number, since 2×1201340001031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1201340000996 and 1201340001014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201340001131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 912391 + ... + 1798648.

It is an arithmetic number, because the mean of its divisors is an integer number (300335788800).

Almost surely, 2^{1201340001031} is an apocalyptic number.

1201340001031 is a deficient number, since it is larger than the sum of its proper divisors (3154169).

1201340001031 is an equidigital number, since it uses as much as digits as its factorization.

1201340001031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3154168.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1201340001031 its reverse (1301000431021), we get a palindrome (2502340432052).

The spelling of 1201340001031 in words is "one trillion, two hundred one billion, three hundred forty million, one thousand, thirty-one".