1201400311 has 4 divisors (see below), whose sum is σ = 1201469824. Its totient is φ = 1201330800.

The previous prime is 1201400309. The next prime is 1201400329. The reversal of 1201400311 is 1130041021.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 1130041021 = 163 ⋅6932767.

It is a cyclic number.

It is not a de Polignac number, because 1201400311 - 2¹ = 1201400309 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1201400291 and 1201400300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201400341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13531 + ... + 50851.

It is an arithmetic number, because the mean of its divisors is an integer number (300367456).

Almost surely, 2^1201400311 is an apocalyptic number.

1201400311 is a deficient number, since it is larger than the sum of its proper divisors (69513).

1201400311 is an equidigital number, since it uses as much as digits as its factorization.

1201400311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69512.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 1201400311 is about 34661.2220067325. Note that the first 3 decimals coincide. The cubic root of 1201400311 is about 1063.0717564168.

Adding to 1201400311 its reverse (1130041021), we get a palindrome (2331441332).

The spelling of 1201400311 in words is "one billion, two hundred one million, four hundred thousand, three hundred eleven".