1201403010113 has 4 divisors (see below), whose sum is σ = 1217860585668. Its totient is φ = 1184945434560.

The previous prime is 1201403010053. The next prime is 1201403010133. The reversal of 1201403010113 is 3110103041021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 293256907024 + 908146103089 = 541532^2 + 952967^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1201403010113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1201403010091 and 1201403010100.

It is not an unprimeable number, because it can be changed into a prime (1201403010133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8228787668 + ... + 8228787813.

It is an arithmetic number, because the mean of its divisors is an integer number (304465146417).

Almost surely, 2^{1201403010113} is an apocalyptic number.

It is an amenable number.

1201403010113 is a deficient number, since it is larger than the sum of its proper divisors (16457575555).

1201403010113 is an equidigital number, since it uses as much as digits as its factorization.

1201403010113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16457575554.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1201403010113 its reverse (3110103041021), we get a palindrome (4311506051134).

The spelling of 1201403010113 in words is "one trillion, two hundred one billion, four hundred three million, ten thousand, one hundred thirteen".