120141111000031 has 8 divisors (see below), whose sum is σ = 131065060518864. Its totient is φ = 109217499870720.

The previous prime is 120141111000013. The next prime is 120141111000067. The reversal of 120141111000031 is 130000111141021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 120141111000031 - 2¹⁷ = 120141110868959 is a prime.

It is a super-3 number, since 3×120141111000031³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120141110999969 and 120141111000014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120141111001031) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 83854740 + ... + 85275433.

It is an arithmetic number, because the mean of its divisors is an integer number (16383132564858).

Almost surely, 2^{120141111000031} is an apocalyptic number.

120141111000031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

120141111000031 is a deficient number, since it is larger than the sum of its proper divisors (10923949518833).

120141111000031 is a wasteful number, since it uses less digits than its factorization.

120141111000031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 169194761.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 120141111000031 its reverse (130000111141021), we get a palindrome (250141222141052).

The spelling of 120141111000031 in words is "one hundred twenty trillion, one hundred forty-one billion, one hundred eleven million, thirty-one", and thus it is an aban number.