120143501 has 2 divisors, whose sum is σ = 120143502. Its totient is φ = 120143500.

The previous prime is 120143497. The next prime is 120143509. The reversal of 120143501 is 105341021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 117202276 + 2941225 = 10826^2 + 1715^2 .

It is a cyclic number.

It is not a de Polignac number, because 120143501 - 2² = 120143497 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 120143501.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120143509) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60071750 + 60071751.

It is an arithmetic number, because the mean of its divisors is an integer number (60071751).

Almost surely, 2^120143501 is an apocalyptic number.

It is an amenable number.

120143501 is a deficient number, since it is larger than the sum of its proper divisors (1).

120143501 is an equidigital number, since it uses as much as digits as its factorization.

120143501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 120143501 is about 10960.9990876744. Note that the first 3 decimals coincide. The cubic root of 120143501 is about 493.4389498225.

Adding to 120143501 its reverse (105341021), we get a palindrome (225484522).

The spelling of 120143501 in words is "one hundred twenty million, one hundred forty-three thousand, five hundred one".