Base | Representation |
---|---|
bin | 10110011000001110… |
… | …11101111001110011 |
3 | 1011000022021222222212 |
4 | 23030013131321303 |
5 | 144101144203042 |
6 | 5304103122335 |
7 | 603505042646 |
oct | 131407357163 |
9 | 34008258885 |
10 | 12014444147 |
11 | 5105927792 |
12 | 23b37433ab |
13 | 1196151164 |
14 | 81d8dba5d |
15 | 4a4b75482 |
hex | 2cc1dde73 |
12014444147 has 2 divisors, whose sum is σ = 12014444148. Its totient is φ = 12014444146.
The previous prime is 12014444107. The next prime is 12014444179. The reversal of 12014444147 is 74144441021.
It is an a-pointer prime, because the next prime (12014444179) can be obtained adding 12014444147 to its sum of digits (32).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12014444147 - 212 = 12014440051 is a prime.
It is a super-2 number, since 2×120144441472 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12014444107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007222073 + 6007222074.
It is an arithmetic number, because the mean of its divisors is an integer number (6007222074).
Almost surely, 212014444147 is an apocalyptic number.
12014444147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12014444147 is an equidigital number, since it uses as much as digits as its factorization.
12014444147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14336, while the sum is 32.
Adding to 12014444147 its reverse (74144441021), we get a palindrome (86158885168).
The spelling of 12014444147 in words is "twelve billion, fourteen million, four hundred forty-four thousand, one hundred forty-seven".
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