12018701389253 has 8 divisors (see below), whose sum is σ = 13244221925088. Its totient is φ = 10836181574064.

The previous prime is 12018701389223. The next prime is 12018701389297. The reversal of 12018701389253 is 35298310781021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12018701389253 - 2²⁴ = 12018684612037 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12018701389223) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10750179575 + ... + 10750180692.

It is an arithmetic number, because the mean of its divisors is an integer number (1655527740636).

Almost surely, 2^{12018701389253} is an apocalyptic number.

12018701389253 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12018701389253 is a deficient number, since it is larger than the sum of its proper divisors (1225520535835).

12018701389253 is a wasteful number, since it uses less digits than its factorization.

12018701389253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21500360323.

The product of its (nonzero) digits is 725760, while the sum is 50.

The spelling of 12018701389253 in words is "twelve trillion, eighteen billion, seven hundred one million, three hundred eighty-nine thousand, two hundred fifty-three".