Base | Representation |
---|---|
bin | 1010111011100110001110… |
… | …0001001001110010010100 |
3 | 1120120000002221121000120100 |
4 | 2232321203201021302110 |
5 | 3033404341430120203 |
6 | 41321240311334100 |
7 | 2350225505315310 |
oct | 256714341116224 |
9 | 46500087530510 |
10 | 12018988129428 |
11 | 3914251512555 |
12 | 142143a981330 |
13 | 692502562227 |
14 | 2d7a17746b40 |
15 | 15c994e12ea3 |
hex | aee63849c94 |
12018988129428 has 144 divisors (see below), whose sum is σ = 36193007410560. Its totient is φ = 3290272876800.
The previous prime is 12018988129409. The next prime is 12018988129439. The reversal of 12018988129428 is 82492188981021.
12018988129428 is a `hidden beast` number, since 1 + 2 + 0 + 1 + 8 + 9 + 88 + 129 + 428 = 666.
It is a Harshad number since it is a multiple of its sum of digits (63).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5319883 + ... + 7234578.
It is an arithmetic number, because the mean of its divisors is an integer number (251340329240).
Almost surely, 212018988129428 is an apocalyptic number.
12018988129428 is a gapful number since it is divisible by the number (18) formed by its first and last digit.
It is an amenable number.
12018988129428 is an abundant number, since it is smaller than the sum of its proper divisors (24174019281132).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12018988129428 is a wasteful number, since it uses less digits than its factorization.
12018988129428 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12554638 (or 12554633 counting only the distinct ones).
The product of its (nonzero) digits is 10616832, while the sum is 63.
The spelling of 12018988129428 in words is "twelve trillion, eighteen billion, nine hundred eighty-eight million, one hundred twenty-nine thousand, four hundred twenty-eight".
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