Base | Representation |
---|---|
bin | 110111111110001111… |
… | …0100111001010010011 |
3 | 102111020221111200010022 |
4 | 1233330132213022103 |
5 | 3432132200001042 |
6 | 131115155054055 |
7 | 11453445100133 |
oct | 1577436471223 |
9 | 374227450108 |
10 | 120200000147 |
11 | 46a818481a7 |
12 | 1b3668a132b |
13 | b447771756 |
14 | 5b63b28ac3 |
15 | 31d780ecd2 |
hex | 1bfc7a7293 |
120200000147 has 2 divisors, whose sum is σ = 120200000148. Its totient is φ = 120200000146.
The previous prime is 120200000119. The next prime is 120200000171. The reversal of 120200000147 is 741000002021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120200000147 - 28 = 120199999891 is a prime.
It is not a weakly prime, because it can be changed into another prime (120200002147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60100000073 + 60100000074.
It is an arithmetic number, because the mean of its divisors is an integer number (60100000074).
Almost surely, 2120200000147 is an apocalyptic number.
120200000147 is a deficient number, since it is larger than the sum of its proper divisors (1).
120200000147 is an equidigital number, since it uses as much as digits as its factorization.
120200000147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 17.
Adding to 120200000147 its reverse (741000002021), we get a palindrome (861200002168).
The spelling of 120200000147 in words is "one hundred twenty billion, two hundred million, one hundred forty-seven", and thus it is an aban number.
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