Base | Representation |
---|---|
bin | 10001011111011100110… |
… | …010000111101111100110 |
3 | 11020220120110001201222102 |
4 | 101133130302013233212 |
5 | 124143144000031042 |
6 | 2320105143332102 |
7 | 152561452303511 |
oct | 21373462075746 |
9 | 4226513051872 |
10 | 1202000002022 |
11 | 423846735226 |
12 | 174b57451032 |
13 | 8946aa62c61 |
14 | 42269dc3d78 |
15 | 2140059db32 |
hex | 117dcc87be6 |
1202000002022 has 4 divisors (see below), whose sum is σ = 1803000003036. Its totient is φ = 601000001010.
The previous prime is 1202000002001. The next prime is 1202000002039. The reversal of 1202000002022 is 2202000002021.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 1202000001994 and 1202000002012.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 300500000504 + ... + 300500000507.
It is an arithmetic number, because the mean of its divisors is an integer number (450750000759).
Almost surely, 21202000002022 is an apocalyptic number.
1202000002022 is a deficient number, since it is larger than the sum of its proper divisors (601000001014).
1202000002022 is an equidigital number, since it uses as much as digits as its factorization.
1202000002022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 601000001013.
The product of its (nonzero) digits is 32, while the sum is 11.
Adding to 1202000002022 its reverse (2202000002021), we get a palindrome (3404000004043).
Subtracting 1202000002022 from its reverse (2202000002021), we obtain a palindrome (999999999999).
The spelling of 1202000002022 in words is "one trillion, two hundred two billion, two thousand, twenty-two".
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