Base | Representation |
---|---|
bin | 10110011000111001… |
… | …01010010100010111 |
3 | 1011000200202021020001 |
4 | 23030130222110113 |
5 | 144104110000043 |
6 | 5304422152131 |
7 | 603603212563 |
oct | 131434522427 |
9 | 34020667201 |
10 | 12020000023 |
11 | 5108a81a19 |
12 | 23b5582647 |
13 | 1197347c65 |
14 | 8205466a3 |
15 | 4a53c174d |
hex | 2cc72a517 |
12020000023 has 2 divisors, whose sum is σ = 12020000024. Its totient is φ = 12020000022.
The previous prime is 12020000017. The next prime is 12020000087. The reversal of 12020000023 is 32000002021.
12020000023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12020000023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12019999964 and 12020000009.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12020000423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010000011 + 6010000012.
It is an arithmetic number, because the mean of its divisors is an integer number (6010000012).
Almost surely, 212020000023 is an apocalyptic number.
12020000023 is a deficient number, since it is larger than the sum of its proper divisors (1).
12020000023 is an equidigital number, since it uses as much as digits as its factorization.
12020000023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 10.
Adding to 12020000023 its reverse (32000002021), we get a palindrome (44020002044).
The spelling of 12020000023 in words is "twelve billion, twenty million, twenty-three", and thus it is an aban number and an uban number.
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