Base | Representation |
---|---|
bin | 11011010101001010001011… |
… | …110110001111111111000101 |
3 | 120202121010120100010101002222 |
4 | 123111022023312033333011 |
5 | 111223334231024001013 |
6 | 1103351414303542125 |
7 | 34214154202355363 |
oct | 3325121366177705 |
9 | 522533510111088 |
10 | 120201301000133 |
11 | 353330a3856031 |
12 | 115939985ba945 |
13 | 520bc1b1440c2 |
14 | 2197ab9c52633 |
15 | dd6aa1e16508 |
hex | 6d528bd8ffc5 |
120201301000133 has 2 divisors, whose sum is σ = 120201301000134. Its totient is φ = 120201301000132.
The previous prime is 120201301000051. The next prime is 120201301000139. The reversal of 120201301000133 is 331000103102021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 106294800943969 + 13906500056164 = 10309937^2 + 3729142^2 .
It is a cyclic number.
It is not a de Polignac number, because 120201301000133 - 226 = 120201233891269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120201301000139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60100650500066 + 60100650500067.
It is an arithmetic number, because the mean of its divisors is an integer number (60100650500067).
Almost surely, 2120201301000133 is an apocalyptic number.
It is an amenable number.
120201301000133 is a deficient number, since it is larger than the sum of its proper divisors (1).
120201301000133 is an equidigital number, since it uses as much as digits as its factorization.
120201301000133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 120201301000133 its reverse (331000103102021), we get a palindrome (451201404102154).
The spelling of 120201301000133 in words is "one hundred twenty trillion, two hundred one billion, three hundred one million, one hundred thirty-three", and thus it is an aban number.
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