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1202020202013 = 32411662545231
BaseRepresentation
bin10001011111011101111…
…111001011011000011101
311020220121212002000011020
4101133131333023120131
5124143214132431023
62320111144314353
7152562116064561
oct21373577133035
94226555060136
101202020202013
11423857081834
12174b621729b9
1389471cb6407
144226c9616a1
152140223dde3
hex117ddfcb61d

1202020202013 has 8 divisors (see below), whose sum is σ = 1609343784576. Its totient is φ = 798021710400.

The previous prime is 1202020202011. The next prime is 1202020202029. The reversal of 1202020202013 is 3102020202021.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1202020202013 - 21 = 1202020202011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1202020201983 and 1202020202001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1202020202011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 831271893 + ... + 831273338.

It is an arithmetic number, because the mean of its divisors is an integer number (201167973072).

Almost surely, 21202020202013 is an apocalyptic number.

It is an amenable number.

1202020202013 is a deficient number, since it is larger than the sum of its proper divisors (407323582563).

1202020202013 is a wasteful number, since it uses less digits than its factorization.

1202020202013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1662545475.

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 1202020202013 its reverse (3102020202021), we get a palindrome (4304040404034).

The spelling of 1202020202013 in words is "one trillion, two hundred two billion, twenty million, two hundred two thousand, thirteen".

Divisors: 1 3 241 723 1662545231 4987635693 400673400671 1202020202013