Base | Representation |
---|---|
bin | 10001011111011101111… |
… | …111001011011000011101 |
3 | 11020220121212002000011020 |
4 | 101133131333023120131 |
5 | 124143214132431023 |
6 | 2320111144314353 |
7 | 152562116064561 |
oct | 21373577133035 |
9 | 4226555060136 |
10 | 1202020202013 |
11 | 423857081834 |
12 | 174b621729b9 |
13 | 89471cb6407 |
14 | 4226c9616a1 |
15 | 2140223dde3 |
hex | 117ddfcb61d |
1202020202013 has 8 divisors (see below), whose sum is σ = 1609343784576. Its totient is φ = 798021710400.
The previous prime is 1202020202011. The next prime is 1202020202029. The reversal of 1202020202013 is 3102020202021.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1202020202013 - 21 = 1202020202011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1202020201983 and 1202020202001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1202020202011) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 831271893 + ... + 831273338.
It is an arithmetic number, because the mean of its divisors is an integer number (201167973072).
Almost surely, 21202020202013 is an apocalyptic number.
It is an amenable number.
1202020202013 is a deficient number, since it is larger than the sum of its proper divisors (407323582563).
1202020202013 is a wasteful number, since it uses less digits than its factorization.
1202020202013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1662545475.
The product of its (nonzero) digits is 96, while the sum is 15.
Adding to 1202020202013 its reverse (3102020202021), we get a palindrome (4304040404034).
The spelling of 1202020202013 in words is "one trillion, two hundred two billion, twenty million, two hundred two thousand, thirteen".
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