Base | Representation |
---|---|
bin | 1110010101000… |
… | …10001100100110 |
3 | 22101011220011202 |
4 | 13022202030212 |
5 | 221232431042 |
6 | 15532202502 |
7 | 2656462133 |
oct | 712421446 |
9 | 271156152 |
10 | 120202022 |
11 | 6193a616 |
12 | 34309432 |
13 | 1bb97b75 |
14 | 11d6d58a |
15 | a845632 |
hex | 72a2326 |
120202022 has 4 divisors (see below), whose sum is σ = 180303036. Its totient is φ = 60101010.
The previous prime is 120202007. The next prime is 120202051. The reversal of 120202022 is 220202021.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 120201994 and 120202012.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30050504 + ... + 30050507.
It is an arithmetic number, because the mean of its divisors is an integer number (45075759).
Almost surely, 2120202022 is an apocalyptic number.
120202022 is a deficient number, since it is larger than the sum of its proper divisors (60101014).
120202022 is an equidigital number, since it uses as much as digits as its factorization.
120202022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60101013.
The product of its (nonzero) digits is 32, while the sum is 11.
The square root of 120202022 is about 10963.6682729824. The cubic root of 120202022 is about 493.5190536242.
Adding to 120202022 its reverse (220202021), we get a palindrome (340404043).
Subtracting 120202022 from its reverse (220202021), we obtain a palindrome (99999999).
The spelling of 120202022 in words is "one hundred twenty million, two hundred two thousand, twenty-two".
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