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12020748533 is a prime number
BaseRepresentation
bin10110011000111111…
…00001000011110101
31011000202011021222122
423030133201003311
5144104302423113
65304450205325
7603612451043
oct131437410365
934022137878
1012020748533
115109443322
1223b5883845
13119754a871
1482069d393
154a54bd408
hex2cc7e10f5

12020748533 has 2 divisors, whose sum is σ = 12020748534. Its totient is φ = 12020748532.

The previous prime is 12020748527. The next prime is 12020748539. The reversal of 12020748533 is 33584702021.

It is a balanced prime because it is at equal distance from previous prime (12020748527) and next prime (12020748539).

It can be written as a sum of positive squares in only one way, i.e., 6491041489 + 5529707044 = 80567^2 + 74362^2 .

It is a cyclic number.

It is not a de Polignac number, because 12020748533 - 210 = 12020747509 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12020748493 and 12020748502.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12020748539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010374266 + 6010374267.

It is an arithmetic number, because the mean of its divisors is an integer number (6010374267).

Almost surely, 212020748533 is an apocalyptic number.

It is an amenable number.

12020748533 is a deficient number, since it is larger than the sum of its proper divisors (1).

12020748533 is an equidigital number, since it uses as much as digits as its factorization.

12020748533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 35.

The spelling of 12020748533 in words is "twelve billion, twenty million, seven hundred forty-eight thousand, five hundred thirty-three".