1202100133151 has 2 divisors, whose sum is σ = 1202100133152. Its totient is φ = 1202100133150.

The previous prime is 1202100133067. The next prime is 1202100133153. The reversal of 1202100133151 is 1513310012021.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1202100133151 is a prime.

Together with 1202100133153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1202100133153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601050066575 + 601050066576.

It is an arithmetic number, because the mean of its divisors is an integer number (601050066576).

Almost surely, 2^{1202100133151} is an apocalyptic number.

1202100133151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1202100133151 is an equidigital number, since it uses as much as digits as its factorization.

1202100133151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 20.

Adding to 1202100133151 its reverse (1513310012021), we get a palindrome (2715410145172).

The spelling of 1202100133151 in words is "one trillion, two hundred two billion, one hundred million, one hundred thirty-three thousand, one hundred fifty-one".