Base | Representation |
---|---|
bin | 10001011111100010110… |
… | …111001101101000000011 |
3 | 11020220211112222210002011 |
4 | 101133202313031220003 |
5 | 124143401103001011 |
6 | 2320123225433351 |
7 | 152564131260214 |
oct | 21374267155003 |
9 | 4226745883064 |
10 | 1202102000131 |
11 | 42389927098a |
12 | 174b8563b857 |
13 | 89485c26076 |
14 | 4227977540b |
15 | 214094ea621 |
hex | 117e2dcda03 |
1202102000131 has 2 divisors, whose sum is σ = 1202102000132. Its totient is φ = 1202102000130.
The previous prime is 1202102000117. The next prime is 1202102000201. The reversal of 1202102000131 is 1310002012021.
It is a weak prime.
It is an emirp because it is prime and its reverse (1310002012021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1202102000131 - 27 = 1202102000003 is a prime.
It is a super-2 number, since 2×12021020001312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1202102000111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601051000065 + 601051000066.
It is an arithmetic number, because the mean of its divisors is an integer number (601051000066).
Almost surely, 21202102000131 is an apocalyptic number.
1202102000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1202102000131 is an equidigital number, since it uses as much as digits as its factorization.
1202102000131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 1202102000131 its reverse (1310002012021), we get a palindrome (2512104012152).
The spelling of 1202102000131 in words is "one trillion, two hundred two billion, one hundred two million, one hundred thirty-one", and thus it is an aban number.
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