1310002012021 has 2 divisors, whose sum is σ = 1310002012022. Its totient is φ = 1310002012020.

The previous prime is 1310002012019. The next prime is 1310002012049. The reversal of 1310002012021 is 1202102000131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1277498970225 + 32503041796 = 1130265^2 + 180286^2 .

It is an emirp because it is prime and its reverse (1202102000131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1310002012021 - 2¹ = 1310002012019 is a prime.

It is a super-2 number, since 2×1310002012021² (a number of 25 digits) contains 22 as substring.

Together with 1310002012019, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1310002011992 and 1310002012010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310002612021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655001006010 + 655001006011.

It is an arithmetic number, because the mean of its divisors is an integer number (655001006011).

Almost surely, 2^{1310002012021} is an apocalyptic number.

It is an amenable number.

1310002012021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310002012021 is an equidigital number, since it uses as much as digits as its factorization.

1310002012021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1310002012021 its reverse (1202102000131), we get a palindrome (2512104012152).

The spelling of 1310002012021 in words is "one trillion, three hundred ten billion, two million, twelve thousand, twenty-one".