Base | Representation |
---|---|
bin | 110111111110100100… |
… | …0111111100101001111 |
3 | 102111021201102010021121 |
4 | 1233331020333211033 |
5 | 3432143021011343 |
6 | 131120233141411 |
7 | 11453641402051 |
oct | 1577510774517 |
9 | 374251363247 |
10 | 120211110223 |
11 | 46a88046386 |
12 | 1b36a55a867 |
13 | b449b61669 |
14 | 5b653bb8d1 |
15 | 31d87a6aed |
hex | 1bfd23f94f |
120211110223 has 2 divisors, whose sum is σ = 120211110224. Its totient is φ = 120211110222.
The previous prime is 120211110199. The next prime is 120211110247. The reversal of 120211110223 is 322011112021.
It is a balanced prime because it is at equal distance from previous prime (120211110199) and next prime (120211110247).
It is a cyclic number.
It is not a de Polignac number, because 120211110223 - 25 = 120211110191 is a prime.
It is a super-2 number, since 2×1202111102232 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 120211110197 and 120211110206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120211110263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60105555111 + 60105555112.
It is an arithmetic number, because the mean of its divisors is an integer number (60105555112).
Almost surely, 2120211110223 is an apocalyptic number.
120211110223 is a deficient number, since it is larger than the sum of its proper divisors (1).
120211110223 is an equidigital number, since it uses as much as digits as its factorization.
120211110223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 120211110223 its reverse (322011112021), we get a palindrome (442222222244).
The spelling of 120211110223 in words is "one hundred twenty billion, two hundred eleven million, one hundred ten thousand, two hundred twenty-three".
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