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120211111201102 = 260105555600551
BaseRepresentation
bin11011010101010011010100…
…100101001100100101001110
3120202122001220000202012220121
4123111103110211030211032
5111224014323431413402
61103400115550335154
734214652253610365
oct3325232445144516
9522561800665817
10120211111201102
1135337278415239
1211595875aba4ba
13520cb2270944c
14219836aaca7dc
15dd6e782d2837
hex6d54d494c94e

120211111201102 has 4 divisors (see below), whose sum is σ = 180316666801656. Its totient is φ = 60105555600550.

The previous prime is 120211111201081. The next prime is 120211111201177. The reversal of 120211111201102 is 201102111112021.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×1202111112011023 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30052777800274 + ... + 30052777800277.

It is an arithmetic number, because the mean of its divisors is an integer number (45079166700414).

Almost surely, 2120211111201102 is an apocalyptic number.

120211111201102 is a deficient number, since it is larger than the sum of its proper divisors (60105555600554).

120211111201102 is an equidigital number, since it uses as much as digits as its factorization.

120211111201102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60105555600553.

The product of its (nonzero) digits is 16, while the sum is 16.

Adding to 120211111201102 its reverse (201102111112021), we get a palindrome (321313222313123).

The spelling of 120211111201102 in words is "one hundred twenty trillion, two hundred eleven billion, one hundred eleven million, two hundred one thousand, one hundred two".

Divisors: 1 2 60105555600551 120211111201102