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120211122000131 is a prime number
BaseRepresentation
bin11011010101010011010101…
…001110011001000100000011
3120202122001220210001212101122
4123111103111032121010003
5111224014334213001011
61103400121014022455
734214652444445421
oct3325232516310403
9522561823055348
10120211122000131
1135337283520758
1211595879647a2b
13520cb24a1a8c6
14219836c2dc111
15dd6e792173db
hex6d54d5399103

120211122000131 has 2 divisors, whose sum is σ = 120211122000132. Its totient is φ = 120211122000130.

The previous prime is 120211122000121. The next prime is 120211122000143. The reversal of 120211122000131 is 131000221112021.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 120211122000131 - 210 = 120211121999107 is a prime.

It is a super-2 number, since 2×1202111220001312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (120211122000121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60105561000065 + 60105561000066.

It is an arithmetic number, because the mean of its divisors is an integer number (60105561000066).

Almost surely, 2120211122000131 is an apocalyptic number.

120211122000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

120211122000131 is an equidigital number, since it uses as much as digits as its factorization.

120211122000131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 120211122000131 its reverse (131000221112021), we get a palindrome (251211343112152).

The spelling of 120211122000131 in words is "one hundred twenty trillion, two hundred eleven billion, one hundred twenty-two million, one hundred thirty-one", and thus it is an aban number.