Base | Representation |
---|---|
bin | 11011010101010011010101… |
… | …001110011001000100000011 |
3 | 120202122001220210001212101122 |
4 | 123111103111032121010003 |
5 | 111224014334213001011 |
6 | 1103400121014022455 |
7 | 34214652444445421 |
oct | 3325232516310403 |
9 | 522561823055348 |
10 | 120211122000131 |
11 | 35337283520758 |
12 | 11595879647a2b |
13 | 520cb24a1a8c6 |
14 | 219836c2dc111 |
15 | dd6e792173db |
hex | 6d54d5399103 |
120211122000131 has 2 divisors, whose sum is σ = 120211122000132. Its totient is φ = 120211122000130.
The previous prime is 120211122000121. The next prime is 120211122000143. The reversal of 120211122000131 is 131000221112021.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120211122000131 - 210 = 120211121999107 is a prime.
It is a super-2 number, since 2×1202111220001312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120211122000121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60105561000065 + 60105561000066.
It is an arithmetic number, because the mean of its divisors is an integer number (60105561000066).
Almost surely, 2120211122000131 is an apocalyptic number.
120211122000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
120211122000131 is an equidigital number, since it uses as much as digits as its factorization.
120211122000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 120211122000131 its reverse (131000221112021), we get a palindrome (251211343112152).
The spelling of 120211122000131 in words is "one hundred twenty trillion, two hundred eleven billion, one hundred twenty-two million, one hundred thirty-one", and thus it is an aban number.
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