12021314471 has 2 divisors, whose sum is σ = 12021314472. Its totient is φ = 12021314470.

The previous prime is 12021314453. The next prime is 12021314489. The reversal of 12021314471 is 17441312021.

It is a balanced prime because it is at equal distance from previous prime (12021314453) and next prime (12021314489).

It is a cyclic number.

It is not a de Polignac number, because 12021314471 - 2²⁶ = 11954205607 is a prime.

It is a super-3 number, since 3×12021314471³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 12021314471.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12021314441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010657235 + 6010657236.

It is an arithmetic number, because the mean of its divisors is an integer number (6010657236).

Almost surely, 2^12021314471 is an apocalyptic number.

12021314471 is a deficient number, since it is larger than the sum of its proper divisors (1).

12021314471 is an equidigital number, since it uses as much as digits as its factorization.

12021314471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 26.

Adding to 12021314471 its reverse (17441312021), we get a palindrome (29462626492).

The spelling of 12021314471 in words is "twelve billion, twenty-one million, three hundred fourteen thousand, four hundred seventy-one".