Base | Representation |
---|---|
bin | 10001011111101000110… |
… | …001010010110111110101 |
3 | 11020221002110111012002002 |
4 | 101133220301102313311 |
5 | 124144101441041203 |
6 | 2320141130025045 |
7 | 152566443563234 |
oct | 21375061226765 |
9 | 4227073435062 |
10 | 1202201112053 |
11 | 42393a206167 |
12 | 174bb2878185 |
13 | 894a0618586 |
14 | 422889b4b1b |
15 | 21413076d88 |
hex | 117e8c52df5 |
1202201112053 has 2 divisors, whose sum is σ = 1202201112054. Its totient is φ = 1202201112052.
The previous prime is 1202201111983. The next prime is 1202201112067. The reversal of 1202201112053 is 3502111022021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 853070209924 + 349130902129 = 923618^2 + 590873^2 .
It is a cyclic number.
It is not a de Polignac number, because 1202201112053 - 222 = 1202196917749 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1202201142053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601100556026 + 601100556027.
It is an arithmetic number, because the mean of its divisors is an integer number (601100556027).
Almost surely, 21202201112053 is an apocalyptic number.
It is an amenable number.
1202201112053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1202201112053 is an equidigital number, since it uses as much as digits as its factorization.
1202201112053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 20.
Adding to 1202201112053 its reverse (3502111022021), we get a palindrome (4704312134074).
The spelling of 1202201112053 in words is "one trillion, two hundred two billion, two hundred one million, one hundred twelve thousand, fifty-three".
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