Base | Representation |
---|---|
bin | 11011010101011011111000… |
… | …111000100110111010010011 |
3 | 120202122221122010021222122112 |
4 | 123111123320320212322103 |
5 | 111224142143403012201 |
6 | 1103404240441055535 |
7 | 34215426234054101 |
oct | 3325337070467223 |
9 | 522587563258575 |
10 | 120220310204051 |
11 | 35340168a78312 |
12 | 115976027875ab |
13 | 521095a484c65 |
14 | 21989a0704c71 |
15 | dd7315bbd0bb |
hex | 6d56f8e26e93 |
120220310204051 has 2 divisors, whose sum is σ = 120220310204052. Its totient is φ = 120220310204050.
The previous prime is 120220310204003. The next prime is 120220310204053. The reversal of 120220310204051 is 150402013022021.
It is a strong prime.
It is an emirp because it is prime and its reverse (150402013022021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 120220310204051 - 210 = 120220310203027 is a prime.
Together with 120220310204053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (120220310204053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60110155102025 + 60110155102026.
It is an arithmetic number, because the mean of its divisors is an integer number (60110155102026).
Almost surely, 2120220310204051 is an apocalyptic number.
120220310204051 is a deficient number, since it is larger than the sum of its proper divisors (1).
120220310204051 is an equidigital number, since it uses as much as digits as its factorization.
120220310204051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 120220310204051 its reverse (150402013022021), we get a palindrome (270622323226072).
The spelling of 120220310204051 in words is "one hundred twenty trillion, two hundred twenty billion, three hundred ten million, two hundred four thousand, fifty-one".
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